How long would a hypothetical protein be from the mRNA sequence 5'cap-GAAUGCAAUACAUCACCGAUGUAAGGUGAGAAAAAAA-polyA-3'?

How long would a hypothetical protein be from the mRNA sequence 5'cap-GAAUGCAAUACAUCACCGAUGUAAGGUGAGAAAAAAA-polyA-3'?

• A. Reading frame 2 produces 2 amino acids
• B. Reading frame 1 produces 2 amino acids
• C. Reading frame 3 produces 8 amino acids
• D. Reading frame 1 produces 10 amino acids

Answer: (C)

To determine how long a hypothetical protein would be from the given mRNA sequence, it's essential to analyze the reading frames and how they translate into amino acids. In this case, reading frame 3 is selected, which produces 8 amino acids. The mRNA sequence begins with the 5' cap and ends with the poly-A tail. If we start translating from the third nucleotide (the 'U' in 'AUG'), we can decode the sequence in triplet codons. By examining the codons in reading frame 3, the translation will yield a series of amino acids until a stop codon is encountered. Counting from that starting point, the segments would be read as follows (with corresponding amino acids for illustration, though specifics aren’t requested): - Starting from the third nucleotide, the sequence is 'UAC ACC GAU UAA GGU GAG AAAAA'. - This translates into specific codons, which leads to a total length of 8 amino acids before reaching a stop codon. Identifying the right reading frame is crucial because starting from the wrong position may yield different sequences and counts of amino acids. Reading frame 3 aligns correctly with the sequence provided, validating why this choice accurately reflects the

To determine how long a hypothetical protein would be from the given mRNA sequence, it's essential to analyze the reading frames and how they translate into amino acids.

In this case, reading frame 3 is selected, which produces 8 amino acids. The mRNA sequence begins with the 5' cap and ends with the poly-A tail. If we start translating from the third nucleotide (the 'U' in 'AUG'), we can decode the sequence in triplet codons. By examining the codons in reading frame 3, the translation will yield a series of amino acids until a stop codon is encountered.

Counting from that starting point, the segments would be read as follows (with corresponding amino acids for illustration, though specifics aren’t requested):

• Starting from the third nucleotide, the sequence is 'UAC ACC GAU UAA GGU GAG AAAAA'.

• This translates into specific codons, which leads to a total length of 8 amino acids before reaching a stop codon.

Identifying the right reading frame is crucial because starting from the wrong position may yield different sequences and counts of amino acids. Reading frame 3 aligns correctly with the sequence provided, validating why this choice accurately reflects the